Reverse the given character string in place without any duplication of characters

program : To reverse the given character string in place without any duplication of characters
#include<iostream.h>
#include<conio.h>
#include<string.h>
char temp[30];
int check(char x,int n)
{
for(int i=0;i<n;i++)
{
if(temp[i]==x)
return 0;
}
return 1;
}
void reverse(char str[],int n)
{
int count=0,i,j,l=0;
for(i=0,j=0;i<n;i++)
{
count=check(str[i],i);
if(count==1)
{
temp[j]=str[i];
j++;
l++;
}
}
cout<<"\nThe reversed character string is:  ";
for(i=l;i>=0;i--)
cout<<temp[i];
}
void main()
{
char str[30],ch;
int n=0;
clrscr();
cout<<"Enter any string  and end with $:  ";
cin.get(ch);
do
{
str[n]=ch;
n++;
cin.get(ch);
}while(ch!='$');
str[n]='';
reverse(str,n);
getch();
}
/* Output:
Enter any string  and end with $:  football$

The reversed character string is:  labtof